2010 AMC 8 Problems/Problem 23
Contents
Problem
Semicircles and pass through the center . What is the ratio of the combined areas of the two semicircles to the area of circle ?
Solution
By the Pythagorean Theorem, the radius of the larger circle turns out to be . Therefore, the area of the larger circle is . Using the coordinate plane given, we find that the radius of each of the two semicircles to be 1. So, the area of the two semicircles is . Finally, the ratio of the combined areas of the two semicircles to the area of circle is .
Solution 2
We first calculate the area of the two semicircles. We can see that the radius is 1, so the area of the two total semi-circles is pi. Using the circle equation, (x-h)^2+(y-k)^2=r^2, we know the centre is (0,0), so the equation becomes x^2+y^2=r^2. We sub in the values that were given to us to find that the radius is sqrt2. Therefore, the area if 2pi. We then find the ratio of them, which is
Video Solution by OmegaLearn
https://youtu.be/abSgjn4Qs34?t=903
~ pi_is_3.14
=Video by MathTalks
Video Solution by WhyMath
~savannahsolver
See Also
2010 AMC 8 (Problems • Answer Key • Resources) | ||
Preceded by Problem 22 |
Followed by Problem 24 | |
1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 | ||
All AJHSME/AMC 8 Problems and Solutions |
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