2023 AMC 8 Problems/Problem 10

Revision as of 19:57, 24 January 2023 by Lpieleanu (talk | contribs) (Solution 1)

Solution 1

Harold made a plum pie. We can distribute into different fractions of pie that the animals ate. First Harold ate $\frac{1}{4}$ of the pie and the remains are $\frac{3}{4}$ of the pie. From this a moose comes and eats $\frac{3}{4} * \frac{1}{3}$ and what remains is $\frac{3}{4} - \frac{1}{4} = \frac{1}{2}$. From this a porcupine comes and eat $\frac{1}{3} * \frac{1}{2} = \frac{1}{6}$ and our final answer of what remains is $\frac{1}{2} - \frac{1}{6} =  \boxed{\text{(D)}\frac{1}{3}}$.


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