2001 AIME II Problems/Problem 5
Problem
A set of positive numbers has the triangle property if it has three distinct elements that are the lengths of the sides of a triangle whose area is positive. Consider sets 
of consecutive positive integers, all of whose ten-element subsets have the triangle property. What is the largest possible value of 
?
Solution 1
Out of all ten-element subsets with distinct elements that do not possess the triangle property, we want to find the one with the smallest maximum element. Call this subset 
. Without loss of generality, consider any 
with 
. 
does not possess the triangle property, so 
. We use this property to build up from the smallest possible 
and 
:
![\[\mathcal{S} = \{\, 4,\, 5,\, 4+5, \,5+(4+5),\, \ldots\,\} = \{4, 5, 9, 14, 23, 37, 60, 97, 157, 254\}\]](http://latex.artofproblemsolving.com/3/e/6/3e6880c0177a3fee7a6008da1235e8d1451d5b32.png)
is the "smallest" ten-element subset without the triangle property, and since the set 
is the largest set of consecutive integers that does not contain this subset, it is also the largest set of consecutive integers in which all ten-element subsets possess the triangle property. Thus, our answer is 
.
See also
| 2001 AIME II (Problems • Answer Key • Resources) | ||
| Preceded by Problem 4 |
Followed by Problem 6 | |
| 1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 | ||
| All AIME Problems and Solutions | ||
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