2021 Fall AMC 10B Problems/Problem 8

Revision as of 10:38, 23 November 2021 by Arcticturn (talk | contribs) (Solution 2)

Problem 8

The largest prime factor of $16384$ is $2$, because $16384 = 2^{14}$. What is the sum of the digits of the largest prime factor of $16383$?

$\textbf{(A) }3\qquad\textbf{(B) }7\qquad\textbf{(C) }10\qquad\textbf{(D) }16\qquad\textbf{(E) }22$

Solution 1

We have

\[16383=16384-1=2^{14}-1=(2^7+1)(2^7-1)=129\cdot127=3\cdot43\cdot127.\] Since $127$ is prime, our answer is $\boxed{\textbf{(C) }10}$.

~kingofpineapplz

Solution 2

Since $16384$ is $2^14$, we can consider it as $(2^7)^2$. $16383$ is $1$ less than $16384$, so it can be considered as $1$ less than a square. Therefore, it can be expressed as $(x-1)(x+1)$. Since $2^7$ is $128, 16383$ is $127 \cdot 129$. $129$ is $3 \cdot 43$, and since $127$ is larger, our answer is $\boxed {(C) 10}$.

~Arcticturn

See Also

2021 Fall AMC 10B (ProblemsAnswer KeyResources)
Preceded by
Problem 7
Followed by
Problem 9
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25
All AMC 10 Problems and Solutions

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