2016 AMC 12B Problems/Problem 5

Problem

The War of $1812$ started with a declaration of war on Thursday, June $18$ , $1812$ . The peace treaty to end the war was signed $919$ days later, on December $24$ , $1814$ . On what day of the week was the treaty signed?

$\textbf{(A)}\ \text{Friday} \qquad \textbf{(B)}\ \text{Saturday} \qquad \textbf{(C)}\ \text{Sunday} \qquad \textbf{(D)}\ \text{Monday} \qquad \textbf{(E)}\ \text{Tuesday}$

Solution

By: dragonfly

To find what day of the week it is in $919$ days, we have to divide $919$ by $7$ to see the remainder, and then add the remainder to the current day. We get that $\frac{919}{7}$ has a remainder of 2, so we increase the current day by $2$ to get $\boxed{\textbf{(B)} \text{Saturday}}$

Question: Why don't we have to account for leap years?

Answer: Although 1812 is a leap year, June 18 is after February 29. Plus, it gives you the number of days...so...

2016 AMC 12B (Problems • Answer Key • Resources)
Preceded by Problem 4	Followed by Problem 6
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All AMC 12 Problems and Solutions

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2016 AMC 12B Problems/Problem 5

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