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1982 AHSME Problems/Problem 16

Revision as of 10:26, 12 October 2020 by Ab2024 (talk | contribs) (Created page with "== Solution for Problem 16 == Each exterior unit square which is removed exposes 4 faces of the unit interior squares, so the entire surface area in square meters is <math>6...")
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Solution for Problem 16

Each exterior unit square which is removed exposes 4 faces of the unit interior squares, so the entire surface area in square meters is $6 \cdot 3^2 - 6 + 24=72.$

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