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1978 AHSME Problems/Problem 14

Revision as of 23:42, 23 October 2018 by Spearra (talk | contribs) (Created page with " Assuming the solutions to the equation are n and m, by Vieta's formulas, <math>n_n + m_n = 18_n</math>. <math>n_n = 10_n</math>, so <math>10_n + m_n = 18_n</math>. <cm...")
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Assuming the solutions to the equation are n and m, by Vieta's formulas, $n_n + m_n = 18_n$.

$n_n = 10_n$, so $10_n + m_n = 18_n$.

\[m_n = 8_n\].

Also by Vieta's formulas, $n_n \cdot m_n = b_n$. \[10_n \cdot 8_n = \boxed{80_n}\].

The answer is (C) $80$

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