2021 AMC 12A Problems/Problem 8

Problem

These problems will not be posted until the 2021 AMC12A is released on Thursday, February 4, 2021.

Solution

It is known that $0.\overline{ab}=\frac{ab}{99}$ and $0.ab=\frac{ab}{100}$ . Let $\overline {ab} = x$ . We have that $66(1+\frac{x}{100})+0.5=66(1+\frac{x}{99})$ . Solving gives that $100x-75=99x$ so $x=75$ . ~aop2014

Note

See problem 1.

2021 AMC 12A (Problems • Answer Key • Resources)
Preceded by Problem 7	Followed by Problem 9
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All AMC 12 Problems and Solutions

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2021 AMC 12A Problems/Problem 8

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Problem

Solution

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