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2006 AMC 12A Problems/Problem 8

Revision as of 19:48, 30 January 2007 by Golddog (talk | contribs) (→‎Solution)

Problem

How many sets of two or more consecutive positive integers have a sum of $15$?

$\mathrm{(A) \ } 1\qquad \mathrm{(B) \ } 2\qquad \mathrm{(C) \ } 3\qquad \mathrm{(D) \ } 4\qquad \mathrm{(E) \ } 5$

Solution

1+2+3+4+5 = 15 4+5+6 = 15 7+8 = 15

The correct answer is C

See also

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