2001 AMC 8 Problems/Problem 21

Problem

The mean of one set of five numbers is 13, and the mean of a separate set of six numbers is 24. What is the mean of the set of all eleven numbers?

$\text{(A)}\ 19 \qquad \text{(B)}\ 24 \qquad \text{(C)}\ 32 \qquad \text{(D)}\ 35 \qquad \text{(E)}\ 40$

Solution

The sum of the numbers from the first set is $5\cdot 13=65$ . The sum of the numbers from the second set is $24\cdot 6 = 144$ . The sum of all the numbers in the set is $144+65=209$ , so the average of the 11 numbers in the set is $209/11=\boxed{19}$ .

2001 AMC 8 (Problems • Answer Key • Resources)
Preceded by Problem 20	Followed by Problem 22
1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25
All AJHSME/AMC 8 Problems and Solutions

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2001 AMC 8 Problems/Problem 21

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