1985 AJHSME Problems/Problem 1
Problem
Solution
We could go at it by just multiplying it out, dividing, etc, but there is a much more simple method.
Noticing that multiplying and dividing by the same number is the equivalent of multiplying (or dividing) by , we can rearrange the numbers in the numerator and the denominator (commutative property of multiplication) so that it looks like
Notice that each number is still there, and nothing has been changed - other than the order.
Finally, since all of the fractions are equal to one, we have , which is equal to .
Thus, is the answer.
See Also
1985 AJHSME (Problems • Answer Key • Resources) | ||
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Followed by Problem 2 | |
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