1958 AHSME Problems/Problem 46

Problem

For values of $x$ less than $1$ but greater than $-4$ , the expression $\frac{x^2 - 2x + 2}{2x - 2}$ has:

$\textbf{(A)}\ \text{no maximum or minimum value}\qquad \\ \textbf{(B)}\ \text{a minimum value of }{+1}\qquad \\ \textbf{(C)}\ \text{a maximum value of }{+1}\qquad \\ \textbf{(D)}\ \text{a minimum value of }{-1}\qquad \\ \textbf{(E)}\ \text{a maximum value of }{-1}$

Solution

$\fbox{}$

1958 AHSC (Problems • Answer Key • Resources)
Preceded by Problem 45	Followed by Problem 47
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1958 AHSME Problems/Problem 46

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