1958 AHSME Problems/Problem 19

Problem

The sides of a right triangle are $a$ and $b$ and the hypotenuse is $c$ . A perpendicular from the vertex divides $c$ into segments $r$ and $s$ , adjacent respectively to $a$ and $b$ . If $a : b = 1 : 3$ , then the ratio of $r$ to $s$ is:

$\textbf{(A)}\ 1 : 3\qquad \textbf{(B)}\ 1 : 9\qquad \textbf{(C)}\ 1 : 10\qquad \textbf{(D)}\ 3 : 10\qquad \textbf{(E)}\ 1 : \sqrt{10}$

Solution

$\fbox{}$

1958 AHSC (Problems • Answer Key • Resources)
Preceded by Problem 18	Followed by Problem 20
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1958 AHSME Problems/Problem 19

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