1991 AHSME Problems/Problem 2

Problem

$|3-\pi|=$

$\textbf{(A)\ }\frac{1}{7}\qquad\textbf{(B)\ }0.14\qquad\textbf{(C)\ }3-\pi\qquad\textbf{(D)\ }3+\pi\qquad\textbf{(E)\ }\pi-3$

Solution

Since $\pi>3$ , the value of $\abs{3-\pi}$ (Error compiling LaTeX. Unknown error_msg) is negative. The absolute value of a negative quantity is the negative quantity multiplied by $-1$ , or the negative of that quantity. Therefore $|3-\pi|=-(3-\pi)=\pi-3$ , which is choice $\boxed{\textbf{E}}$ The problems on this page are copyrighted by the Mathematical Association of America's American Mathematics Competitions.

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1991 AHSME Problems/Problem 2

Problem

Solution