2011 AIME II Problems/Problem 2

Revision as of 21:26, 30 March 2011 by Pkustar (talk | contribs)

Problem:

On square ABCD, point E lies on side AD and point F lies on side BC, so that BE=EF=FD=30. Find the area of the square ABCD.


Solution:

Drawing the square and examining the given lengths, you find that the three segments cut the square into three equal horizontal sections (I dont know how to make a diagram so somebody please insert one) Therefore, (x being the side length), $sqrt(x^2+(x/3)^2)=900$.