1951 AHSME Problems/Problem 2

Problem

A rectangular field is half as wide as it is long and is completely enclosed by $x$ yards of fencing. The area in terms of $x$ is:

$(\mathrm{A})\ \frac{x^2}2 \qquad (\mathrm{B})\ 2x^2 \qquad (\mathrm{C})\ \frac{2x^2}9 \qquad (\mathrm{D})\ \frac{x^2}{18} \qquad (\mathrm{E})\ \frac{x^2}{72}$

Solution

By definition of a percent, the answer is $\mathrm{(B)}$ .

1951 AHSME (Problems • Answer Key • Resources)
Preceded by Problem 1	Followed by Problem 3
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1951 AHSME Problems/Problem 2

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