1959 AHSME Problems/Problem 46

Problem

A student on vacation for $d$ days observed that (1) it rained $7$ times, morning or afternoon (2) when it rained in the afternoon, it was clear in the morning (3) there were five clear afternoons (4) there were six clear mornings. Then $d$ equals: $\textbf{(A)}\ 7\qquad\textbf{(B)}\ 9\qquad\textbf{(C)}\ 10\qquad\textbf{(D)}\ 11\qquad\textbf{(E)}\ 12$

Solution

From the given information, we know that there were $7+5+6=18$ halves of the day (either afternoons or mornings), so there were $\frac{18}{2}=9$ days in total, which is answer choice $\boxed{\textbf{(B)}}$ .

1959 AHSC (Problems • Answer Key • Resources)
Preceded by Problem 45	Followed by Problem 47
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1959 AHSME Problems/Problem 46

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