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2002 OIM Problems/Problem 4

Revision as of 03:43, 14 December 2023 by Tomasdiaz (talk | contribs)

Problem

In a scalene triangle $ABC$, the interior bisector $BD$ is drawn, with $D$ on $AC$. Let $E$ and $F$, respectively, be the feet of the perpendiculars drawn from $A$ and $C$ towards the line $BD$, and let $M$ be the point on side $BC$ such that $DM$ is perpendicular to $BC$. Show that $\angle EMD = \angle DMF$.

~translated into English by Tomas Diaz. ~orders@tomasdiaz.com

Solution

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See also

https://www.oma.org.ar/enunciados/ibe18.htm

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