2010 AMC 8 Problems/Problem 6

Problem

Which of the following figures has the greatest number of lines of symmetry?

$\textbf{(A)}\ \text{equilateral triangle}$

$\textbf{(B)}\ \text{non-square rhombus}$

$\textbf{(C)}\ \text{non-square rectangle}$

$\textbf{(D)}\ \text{isosceles trapezoid}$

$\textbf{(E)}\ \text{square}$

Solution

An equilateral triangle has $3$ lines of symmetry. A non-square rhombus has $2$ lines of symmetry. A non-square rectangle has $2$ lines of symmetry. An isosceles trapezoid has $1$ line of symmetry. A square has $4$ lines of symmetry.

Therefore, the answer is $\boxed{ \textbf{(E)}\ \text{square} }$ .

Video Solution by @MathTalks

https://youtu.be/RhyRqHMXvq0?si=m1R2q8UnLRD-KksT

Video Solution by WhyMath

https://youtu.be/hoZO5M0raTI

2010 AMC 8 (Problems • Answer Key • Resources)
Preceded by Problem 5	Followed by Problem 7
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All AJHSME/AMC 8 Problems and Solutions

The problems on this page are copyrighted by the Mathematical Association of America's American Mathematics Competitions.

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2010 AMC 8 Problems/Problem 6

Contents

Problem

Solution

Video Solution by @MathTalks

Video Solution by WhyMath

See Also