2020 AMC 8 Problems/Problem 2

Problem 2

Four friends do yardwork for their neighbors over the weekend, earning $$15, $20, $25,$ and $$40,$ respectively. They decide to split their earnings equally among themselves. In total how much will the friend who earned $$40$ give to the others?

$\textbf{(A) }$5 \qquad \textbf{(B) }$10 \qquad \textbf{(C) }$15 \qquad \textbf{(D) }$20 \qquad \textbf{(E) }$25$

Solution

First we average $15,20,25,40$ to get $25$ . Thus, $40 - 25 = \boxed{\textbf{(C) }$15.}$ . ~~Spaced_Out Note if you get $100 once adding it up and then /4=$ 15 or \boxed{\textbf{(C) }. $oceanxia ==Solution 2== The total earnings for the four friends is$ $15+$20+$25+$40=$100 $. Since they decided to split their earnings equally among themselves, it follows that each person will get$ \frac{$100}{4}=$25 $. Since the friend who earned$ $40 $will need to leave with$ $25 $, he will have to give$ $40-$25=$15 $to the others$ \implies\boxed{\textbf{(C) }$15}$.
~junaidmansuri

Video Solution

https://youtu.be/-mSgttsOv2Y

~savannahsolver

2020 AMC 8 (Problems • Answer Key • Resources)
Preceded by Problem 1	Followed by Problem 3
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2020 AMC 8 Problems/Problem 2

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Problem 2

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Video Solution

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