2020 AMC 10A Problems/Problem 18
Problem
Let be an ordered quadruple of not necessarily distinct integers, each one of them in the set For how many such quadruples is it true that is odd? (For example, is one such quadruple, because is odd.)
Solution
In order for to be odd, consider parity. We must have an even number minus an odd number or an odd number minus an even number.
See Also
2020 AMC 10A (Problems • Answer Key • Resources) | ||
Preceded by Problem 17 |
Followed by Problem 19 | |
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