Difference between revisions of "Power set"

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The '''power set''' of a given [[set]] <math>S</math> is the set <math>P(S)</math> of [[subset]]s of that set.   
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The '''power set''' of a given [[set]] <math>S</math> is the set <math>\mathcal{P}(S)</math> of [[subset]]s of that set.   
  
The [[empty set]] has only one subset, itself.  Thus <math>P(\emptyset) = \{\emptyset\}</math>.
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The [[empty set]] has only one subset, itself.  Thus <math>\mathcal{P}(\emptyset) = \{\emptyset\}</math>.
  
A set <math>\{a\}</math> with a single element has two subsets, the empty set and the entire set.  Thus <math>P(\{a\}) = \{\emptyset, \{a\}\}</math>.
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A set <math>\{a\}</math> with a single element has two subsets, the empty set and the entire set.  Thus <math>\mathcal{P}(\{a\}) = \{\emptyset, \{a\}\}</math>.
  
A set <math>\{a, b\}</math> with two elements has four subsets, and <math>P(\{a, b\}) = \{\emptyset, \{a\}, \{b\}, \{a, b\}\}</math>.
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A set <math>\{a, b\}</math> with two elements has four subsets, and <math>\mathcal{P}(\{a, b\}) = \{\emptyset, \{a\}, \{b\}, \{a, b\}\}</math>.
  
 
Similarly, for any [[finite]] set with <math>n</math> elements, the power set has <math>2^n</math> elements.
 
Similarly, for any [[finite]] set with <math>n</math> elements, the power set has <math>2^n</math> elements.
  
Note that for [[nonnegative]] [[integer]]s, <math>2^n > n</math> so the power set of any set is larger than the set itself.  An analogous result holds for [[infinite]] sets: for any set <math>S</math>, there is no [[bijection]] between <math>S</math> and <math>P(S)</math> (or equivalently, there is no [[injection]] from <math>P(S)</math> to <math>S</math>).
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Note that for [[nonnegative]] [[integer]]s, <math>2^n > n</math> so the power set of any set is larger than the set itself.  An analogous result holds for [[infinite]] sets: for any set <math>S</math>, there is no [[bijection]] between <math>S</math> and <math>\mathcal{P}(S)</math> (or equivalently, there is no [[injection]] from <math>\mathcal{P}(S)</math> to <math>S</math>).
  
 
===Proof===
 
===Proof===

Revision as of 17:06, 23 August 2006

The power set of a given set $S$ is the set $\mathcal{P}(S)$ of subsets of that set.

The empty set has only one subset, itself. Thus $\mathcal{P}(\emptyset) = \{\emptyset\}$.

A set $\{a\}$ with a single element has two subsets, the empty set and the entire set. Thus $\mathcal{P}(\{a\}) = \{\emptyset, \{a\}\}$.

A set $\{a, b\}$ with two elements has four subsets, and $\mathcal{P}(\{a, b\}) = \{\emptyset, \{a\}, \{b\}, \{a, b\}\}$.

Similarly, for any finite set with $n$ elements, the power set has $2^n$ elements.

Note that for nonnegative integers, $2^n > n$ so the power set of any set is larger than the set itself. An analogous result holds for infinite sets: for any set $S$, there is no bijection between $S$ and $\mathcal{P}(S)$ (or equivalently, there is no injection from $\mathcal{P}(S)$ to $S$).

Proof

See Also

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