Difference between revisions of "Euler's Four-Square Identity"
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''The product of the sum of the four squares is itself, the sum of four squares.'' | ''The product of the sum of the four squares is itself, the sum of four squares.'' | ||
− | Mathematically, for any eight [[Complex numbers|complex numbers]] <math>x_1,x_2, x_3, x_4, y_1, y_2, y_3, y_4</math>, we must have <cmath>(x_1^2+ x_2^2 + x_3 ^2 + x_4^2)(y_1^2+y_2^2+y_3^2+y_4^2)</cmath> <cmath>=(x_1y_1+x_2y_2+x_3y_3+x_4y_4)^2</cmath> <cmath>+(x_1y_2-x_2y_1+x_3y_4-x_4y_3)^2</cmath> <cmath>+(x_1y_3-x_3y_1+x_4y_2-x_2y_4)^2</cmath> <cmath>+(x_1y_4-x_4y_1 + x_2y_3 - x_3y_2)^2</cmath> | + | Mathematically, for any eight [[Complex numbers|complex numbers]] <math>x_1,x_2, x_3, x_4, y_1, y_2, y_3, y_4</math>, we must have <cmath>(x_1^2+ x_2^2 + x_3 ^2 + x_4^2)(y_1^2+y_2^2+y_3^2+y_4^2)</cmath> <cmath>=(x_1y_1+x_2y_2+x_3y_3+x_4y_4)^2</cmath> <cmath>+(x_1y_2-x_2y_1+x_3y_4-x_4y_3)^2</cmath> <cmath>+(x_1y_3-x_3y_1+x_4y_2-x_2y_4)^2</cmath> <cmath>+(x_1y_4-x_4y_1 + x_2y_3 - x_3y_2)^2.</cmath> |
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+ | ==Proof== |
Revision as of 11:42, 11 August 2018
Identity
The product of the sum of the four squares is itself, the sum of four squares.
Mathematically, for any eight complex numbers , we must have