Art of Problem Solving
AoPS Online
Math texts, online classes, and more
for students in grades 5-12.
Visit AoPS Online ‚
Books for Grades 5-12 Online Courses
Beast Academy
Engaging math books and online learning
for students ages 6-13.
Visit Beast Academy ‚
Books for Ages 6-13 Beast Academy Online
AoPS Academy
Small live classes for advanced math
and language arts learners in grades 2-12.
Visit AoPS Academy ‚
Find a Physical Campus Visit the Virtual Campus

Difference between revisions of "2017 AMC 8 Problems/Problem 1"

m (→‎Solution 2)
(→‎Solution 1)
Line 7: Line 7:
 
==Solution 1==
 
==Solution 1==
 
We compute each expression individually according to the order of operations. We get <math>2 + 0 + 1 + 7 = 10</math>, <math>2 \times 0 + 1 + 7 = 8</math>, <math>2 + 0 \times 1 + 7 = 9</math>, <math>2 + 0 + 1 \times 7 = 9</math>, and <math>2 \times 0 \times 1 \times 7 = 0</math>. Since <math>10</math> is the greatest out of these numbers, <math>\boxed{\textbf{(A) }2+0+1+7}</math> is the answer.
 
We compute each expression individually according to the order of operations. We get <math>2 + 0 + 1 + 7 = 10</math>, <math>2 \times 0 + 1 + 7 = 8</math>, <math>2 + 0 \times 1 + 7 = 9</math>, <math>2 + 0 + 1 \times 7 = 9</math>, and <math>2 \times 0 \times 1 \times 7 = 0</math>. Since <math>10</math> is the greatest out of these numbers, <math>\boxed{\textbf{(A) }2+0+1+7}</math> is the answer.
 +
 +
==Solution 1==
 +
We immediately see that each of the other choices, except for A, has a number multiplied by <math>0</math>. This will only make the expression's value smaller, obviously. Therefore <math>\boxed{\textbf{(A) }2+0+1+7}</math> is your answer
  
 
==See Also==
 
==See Also==

Revision as of 02:40, 10 August 2018

Problem 1

Which of the following values is largest?

$\textbf{(A) }2+0+1+7\qquad\textbf{(B) }2 \times 0 +1+7\qquad\textbf{(C) }2+0 \times 1 + 7\qquad\textbf{(D) }2+0+1 \times 7\qquad\textbf{(E) }2 \times 0 \times 1 \times 7$

Solution 1

We compute each expression individually according to the order of operations. We get $2 + 0 + 1 + 7 = 10$, $2 \times 0 + 1 + 7 = 8$, $2 + 0 \times 1 + 7 = 9$, $2 + 0 + 1 \times 7 = 9$, and $2 \times 0 \times 1 \times 7 = 0$. Since $10$ is the greatest out of these numbers, $\boxed{\textbf{(A) }2+0+1+7}$ is the answer.

Solution 1

We immediately see that each of the other choices, except for A, has a number multiplied by $0$. This will only make the expression's value smaller, obviously. Therefore $\boxed{\textbf{(A) }2+0+1+7}$ is your answer

See Also

2017 AMC 8 (Problems • Answer Key • Resources)
Preceded by
First Problem 		Followed by
Problem 2
1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25
All AJHSME/AMC 8 Problems and Solutions

The problems on this page are copyrighted by the Mathematical Association of America's American Mathematics Competitions. AMC logo.png

Retrieved from "https://artofproblemsolving.com/wiki/index.php?title=2017_AMC_8_Problems/Problem_1&oldid=97126"