Difference between revisions of "1973 AHSME Problems/Problem 13"
Rockmanex3 (talk | contribs) (Solution to Problem 13 (credit to gaussintraining)) |
Rockmanex3 (talk | contribs) m (→Solution) |
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Squaring the expression and taking the positive square root (since numerator and denominator are positive) of the result yields | Squaring the expression and taking the positive square root (since numerator and denominator are positive) of the result yields | ||
− | <cmath>\sqrt{(\frac{2(\sqrt2+\sqrt6)}{3\sqrt{2+\sqrt3}})^2}</cmath> | + | <cmath>\sqrt{\left(\frac{2(\sqrt2+\sqrt6)}{3\sqrt{2+\sqrt3}}\right)^2}</cmath> |
− | <cmath>\sqrt{\frac{4(2+4\sqrt{3}+6)}{9(2+\sqrt{3}}}</cmath> | + | <cmath>\sqrt{\frac{4(2+4\sqrt{3}+6)}{9(2+\sqrt{3})}}</cmath> |
− | <cmath>\sqrt{\frac{4(8+4\sqrt{3})}{9(2+\sqrt{3}}}</cmath> | + | <cmath>\sqrt{\frac{4(8+4\sqrt{3})}{9(2+\sqrt{3})}}</cmath> |
<cmath>\sqrt{\frac{16}{9}}</cmath> | <cmath>\sqrt{\frac{16}{9}}</cmath> | ||
<cmath>\frac43</cmath> | <cmath>\frac43</cmath> |
Revision as of 16:32, 27 July 2018
Problem
The fraction is equal to
Solution
Squaring the expression and taking the positive square root (since numerator and denominator are positive) of the result yields
The answer is .
See Also
1973 AHSC (Problems • Answer Key • Resources) | ||
Preceded by Problem 12 |
Followed by Problem 14 | |
1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 • 26 • 27 • 28 • 29 • 30 • 31 • 32 • 33 • 34 • 35 | ||
All AHSME Problems and Solutions |