Difference between revisions of "2018 AIME I Problems/Problem 4"

(Solution 1)
(Solution 1)
Line 3: Line 3:
  
 
==Solution 1==
 
==Solution 1==
<center><asy>import cse5;
+
<center>
 +
[asy]
 +
syimport cse5;
 
unitsize(10mm);
 
unitsize(10mm);
 
pathpen=black;
 
pathpen=black;
Line 10: Line 12:
 
pair B = (0,0), pair A = (6,8), pair C = (12,0)
 
pair B = (0,0), pair A = (6,8), pair C = (12,0)
  
</asy></center>
+
[/asy]
 +
</center>

Revision as of 17:44, 7 March 2018

Problem 4

In $\triangle ABC, AB = AC = 10$ and $BC = 12$. Point $D$ lies strictly between $A$ and $B$ on $\overline{AB}$ and point $E$ lies strictly between $A$ and $C$ on $\overline{AC}$) so that $AD = DE = EC$. Then $AD$ can be expressed in the form $\dfrac{p}{q}$, where $p$ and $q$ are relatively prime positive integers. Find $p+q$.

Solution 1

[asy] syimport cse5; unitsize(10mm); pathpen=black; dotfactor=3;

pair B = (0,0), pair A = (6,8), pair C = (12,0)

[/asy]