A three-dimensional rectangular box with dimensions <math>X</math>, <math>Y</math>, and <math>Z</math> has faces whose surface areas are <math>1746</math>, <math>1746</math>, <math>1854</math>, <math>1854</math>, <math>9991</math>, and <math>9991</math> square units. What is <math>X</math> + <math>Y</math> + <math>Z</math>?
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Solution 1(Currently Only the Answer is present, someone must give the solution)