Difference between revisions of "2018 AMC 10A Problems/Problem 11"

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<math>\textbf{(A) }  42  \qquad        \textbf{(B) }  49  \qquad    \textbf{(C) }  56  \qquad  \textbf{(D) }  63 \qquad  \textbf{(E) }  84 </math>
 
<math>\textbf{(A) }  42  \qquad        \textbf{(B) }  49  \qquad    \textbf{(C) }  56  \qquad  \textbf{(D) }  63 \qquad  \textbf{(E) }  84 </math>
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== See Also ==
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{{AMC10 box|year=2018|ab=A|num-b=10|num-a=12}}
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{{MAA Notice}}

Revision as of 14:58, 8 February 2018

When 7 fair standard 6-sided dice are thrown, the probability that the sum of the numbers on the top faces is 10 can be written as \[\frac{n}{6^7},\]where $n$ is a positive integer. What is $n$?

$\textbf{(A) }   42   \qquad        \textbf{(B) }   49   \qquad    \textbf{(C) }   56   \qquad   \textbf{(D) }  63 \qquad  \textbf{(E) }   84$

See Also

2018 AMC 10A (ProblemsAnswer KeyResources)
Preceded by
Problem 10
Followed by
Problem 12
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25
All AMC 10 Problems and Solutions

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