Difference between revisions of "1990 AJHSME Problems/Problem 13"
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After the first ounce, there are <math>3.5</math> ounces left. Thus, it is required to pay for <math>3</math> ounces and then the extra half. | After the first ounce, there are <math>3.5</math> ounces left. Thus, it is required to pay for <math>3</math> ounces and then the extra half. | ||
| − | The total price is <math>30+4\times 22=107</math> cents. The extra half is charged because in the problem it says, "or for a a fraction of an ounce". So, you need to add 22. The answer is choice <math>\boxed{\textbf{( | + | The total price is <math>30+4\times 22=107</math> cents. The extra half is charged because in the problem it says, "or for a a fraction of an ounce". So, you need to add 22. The answer is choice <math>\boxed{\textbf{(C)}~\mathbf{1.18}~\textbf{dollars}}</math>. |
==See Also== | ==See Also== | ||
Revision as of 20:26, 13 November 2017
Problem
One proposal for new postage rates for a letter was 
cents for the first ounce and 
cents for each additional ounce (or fraction of an ounce). The postage for a letter weighing 
ounces was
Solution
After the first ounce, there are 
ounces left. Thus, it is required to pay for 
ounces and then the extra half.
The total price is 
cents. The extra half is charged because in the problem it says, "or for a a fraction of an ounce". So, you need to add 22. The answer is choice 
.
See Also
| 1990 AJHSME (Problems • Answer Key • Resources) | ||
| Preceded by Problem 12 |
Followed by Problem 14 | |
| 1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 | ||
| All AJHSME/AMC 8 Problems and Solutions | ||
The problems on this page are copyrighted by the Mathematical Association of America's American Mathematics Competitions. 
