Difference between revisions of "1983 AIME Problems/Problem 11"

Revision as of 23:17, 23 July 2006

Problem

The solid shown has a square base of side length $s$ . The upper edge is parallel to the base and has length $2s$ . All edges have length $s$ . Given that $s=6\sqrt{2}$ , what is the volume of the solid? [img]http://www.artofproblemsolving.com/Forum/album_pic.php?pic_id=791&sid=cfd5dae222dd7b8944719b56de7b8bf7[/img]

An image is supposed to go here. You can help us out by creating one and editing it in. Thanks.

Solution

First, we find the height of the figure by drawing a perpendicular from the midpoint of $AD$ to $EF$ . The hypotenuse of the triangle is the median of equilateral triangle $ADE$ one of the legs is $3\sqrt{2}$ . We apply the pythagorean theorem to find that the height is equal to $6$ .

Next, we complete the figure into a triangular prism, and find the area, which is $\frac{6\sqrt{2}\cdot 12\sqrt{2}\cdot 6}{2}=432$ .

Now, we subtract off the two extra pyramids that we included, whose combined area is $2\cdot \left( \frac{12\sqrt{2}\cdot 3\sqrt{2} \cdot 6}{3} \right)=144$ .

Thus, our answer is $432-144=288$ .

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 The solid shown has a square base of side length <math>s</math>. The upper edge is parallel to the base and has length <math>2s</math>. All edges have length <math>s</math>. Given that <math>s=6\sqrt{2}</math>, what is the volume of the solid?
 [img]http://www.artofproblemsolving.com/Forum/album_pic.php?pic_id=791&sid=cfd5dae222dd7b8944719b56de7b8bf7[/img]
-{{img}}
+{{image}}
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Difference between revisions of "1983 AIME Problems/Problem 11"

Revision as of 23:17, 23 July 2006

Problem

Solution

See also