Difference between revisions of "1984 AHSME Problems/Problem 3"

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==Problem==
 
==Problem==
Let <math> n </math> be the smallest nonprime [[integer]] greater than <math> 1 </math> with no [[Prime factorization|prime factor]] less than <math> 10 </math>. Then  
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Let <math> n </math> be the smallest nonprime [[integoobs]] greater than <math> 1 </math> with no [[Prime factorization|prime factor]] less than <math> 10 </math>. Then  
  
 
<math> \mathrm{(A) \ }100<n\leq110 \qquad \mathrm{(B) \ }110<n\leq120 \qquad \mathrm{(C) \ } 120<n\leq130 \qquad \mathrm{(D) \ }130<n\leq140 \qquad \mathrm{(E) \ } 140<n\leq150 </math>
 
<math> \mathrm{(A) \ }100<n\leq110 \qquad \mathrm{(B) \ }110<n\leq120 \qquad \mathrm{(C) \ } 120<n\leq130 \qquad \mathrm{(D) \ }130<n\leq140 \qquad \mathrm{(E) \ } 140<n\leq150 </math>

Revision as of 19:31, 7 November 2016

Problem

Let $n$ be the smallest nonprime integoobs greater than $1$ with no prime factor less than $10$. Then

$\mathrm{(A) \ }100<n\leq110 \qquad \mathrm{(B) \ }110<n\leq120 \qquad \mathrm{(C) \ } 120<n\leq130 \qquad \mathrm{(D) \ }130<n\leq140 \qquad \mathrm{(E) \ } 140<n\leq150$

Solution

To solve the problem, you would have to find the smallest prime number greater than ten: eleven. So, the smallest number with eleven as prime factorization and greater than 100 = 11^2 (i.e. 121). Which is in $\boxed{\text{C}}$.

See Also

1984 AHSME (ProblemsAnswer KeyResources)
Preceded by
Problem 2
Followed by
Problem 4
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30
All AHSME Problems and Solutions

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