Difference between revisions of "2005 AMC 8 Problems/Problem 6"
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− | + | The problems on this page are copyrighted by the Mathematical Association of America's American Mathematics Competitions. AMC logo.png and do not sponsor or endorse this. |
Revision as of 17:21, 24 September 2016
Problem
Suppose is a digit. For how many values of is ?
Solution
We see that works but does not. The digit can be from through , which is values.
See Also
2005 AMC 8 (Problems • Answer Key • Resources) | ||
Preceded by Problem 5 |
Followed by Problem 7 | |
1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 | ||
All AJHSME/AMC 8 Problems and Solutions |
The problems on this page are copyrighted by the Mathematical Association of America's American Mathematics Competitions. AMC logo.png and do not sponsor or endorse this.