Difference between revisions of "1966 AHSME Problems/Problem 6"

(Solution)
Line 5: Line 5:
  
 
== Solution ==
 
== Solution ==
 +
<asy>
 +
draw(unitcircle);
 +
draw((-1,0)--(1,0)--(1/2, sqrt(3)/2)--cycle);
 +
label( "A", (-1,0), W);
 +
label( "B", (1,0), E);
 +
label( "C", (1/2, sqrt(3)/2), N);
 +
</asy>
 +
 
<math>\fbox{C}</math>
 
<math>\fbox{C}</math>
  

Revision as of 00:42, 26 June 2016

Problem

$AB$ is the diameter of a circle centered at $O$. $C$ is a point on the circle such that angle $BOC$ is $60^\circ$. If the diameter of the circle is $5$ inches, the length of chord $AC$, expressed in inches, is:

$\text{(A)} \ 3 \qquad \text{(B)} \ \frac {5\sqrt {2}}{2} \qquad \text{(C)} \frac {5\sqrt3}{2} \ \qquad \text{(D)} \ 3\sqrt3 \qquad \text{(E)} \ \text{none of these}$

Solution

[asy] draw(unitcircle); draw((-1,0)--(1,0)--(1/2, sqrt(3)/2)--cycle); label( "A", (-1,0), W); label( "B", (1,0), E); label( "C", (1/2, sqrt(3)/2), N); [/asy]

$\fbox{C}$

See also

1966 AHSME (ProblemsAnswer KeyResources)
Preceded by
Problem 5
Followed by
Problem 7
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30
All AHSME Problems and Solutions

The problems on this page are copyrighted by the Mathematical Association of America's American Mathematics Competitions. AMC logo.png