Difference between revisions of "1983 AHSME Problems/Problem 5"
Quantummech (talk | contribs) (Created page with "==Problem 5== Triangle <math>ABC</math> has a right angle at <math>C</math>. If <math>\sin A = \frac{2}{3}</math>, then <math>\tan B</math> is <math>\textbf{(A)}\ \frac{3}{5}...") |
Quantummech (talk | contribs) (→Solution) |
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| Line 9: | Line 9: | ||
C=(0,0); | C=(0,0); | ||
pair A,B,C; | pair A,B,C; | ||
| − | draw A--B--C--A | + | draw A--B--C--A; |
</asy> | </asy> | ||
| + | |||
==See Also== | ==See Also== | ||
{{AHSME box|year=1983|num-b=4|num-a=6}} | {{AHSME box|year=1983|num-b=4|num-a=6}} | ||
{{MAA Notice}} | {{MAA Notice}} | ||
Revision as of 06:25, 18 May 2016
Problem 5
Triangle 
has a right angle at 
. If 
, then 
is
Solution
A=(0,1.7); B=(2,0); C=(0,0); pair A,B,C; draw A--B--C--A; (Error making remote request. Unknown error_msg)
See Also
| 1983 AHSME (Problems • Answer Key • Resources) | ||
| Preceded by Problem 4 |
Followed by Problem 6 | |
| 1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 • 26 • 27 • 28 • 29 • 30 | ||
| All AHSME Problems and Solutions | ||
The problems on this page are copyrighted by the Mathematical Association of America's American Mathematics Competitions. 
