Difference between revisions of "2015 AMC 8 Problems/Problem 1"
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==Solution 2== | ==Solution 2== | ||
| − | Since there are <math>3</math> feet in a yard, we divide <math>9</math> by <math>3</math> to get <math>3</math>, and <math>12</math> by <math>3</math> to get <math>4</math>. To find the area of the carpet, we then multiply these two values together to get <math>\boxed{\textbf{(A)}~12}</math> | + | Since there are <math>3</math> feet in a yard, we divide <math>9</math> by <math>3</math> to get <math>3</math>, and <math>12</math> by <math>3</math> to get <math>4</math>. To find the area of the carpet, we then multiply these two values together to get <math>\boxed{\textbf{(A)}~12}</math>. |
==See Also== | ==See Also== | ||
{{AMC8 box|year=2015|before=First Problem|num-a=2}} | {{AMC8 box|year=2015|before=First Problem|num-a=2}} | ||
{{MAA Notice}} | {{MAA Notice}} | ||
Revision as of 10:07, 3 March 2016
How many square yards of carpet are required to cover a rectangular floor that is 
feet long and 
feet wide? (There are 3 feet in a yard.)
Solution
First, we multiply 
to get that you need 
square feet of carpet you need to cover. Since there are square feet in a square yard, you divide by to get square yards, so our answer is 
.
Solution 2
Since there are 
feet in a yard, we divide by to get , and by to get 
. To find the area of the carpet, we then multiply these two values together to get 
.
See Also
| 2015 AMC 8 (Problems • Answer Key • Resources) | ||
| Preceded by First Problem |
Followed by Problem 2 | |
| 1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 | ||
| All AJHSME/AMC 8 Problems and Solutions | ||
The problems on this page are copyrighted by the Mathematical Association of America's American Mathematics Competitions. 
