Difference between revisions of "Trigonometric substitution"
Quantum leap (talk | contribs) |
|||
Line 1: | Line 1: | ||
− | Trigonometric substitution is the technique of replacing | + | '''Trigonometric substitution''' is the technique of replacing [[variable]]s in equations with <math>\sin \theta\,</math> or <math>\cos {\theta}\,</math> or other [[function]]s from [[trigonometry]]. |
− | In calculus, it is used to evaluate | + | In [[calculus]], it is used to evaluate [[integral]]s of [[expression]]s such as <math>\sqrt{a^2+x^2},\sqrt{a^2-x^2}</math> or <math>\sqrt{x^2-a^2}</math> |
− | |||
− | + | == Examples == | |
− | == <math>\sqrt{a^2+x^2}</math> == | + | === <math>\sqrt{a^2+x^2}</math> === |
To evaluate an expression such as <math>\int \sqrt{a^2+x^2}\,dx</math>, we make use of the identity <math>\tan^2x+1=\sec^2x</math>. Set <math>x=a\tan\theta</math> and the radical will go away. | To evaluate an expression such as <math>\int \sqrt{a^2+x^2}\,dx</math>, we make use of the identity <math>\tan^2x+1=\sec^2x</math>. Set <math>x=a\tan\theta</math> and the radical will go away. | ||
− | == <math>\sqrt{a^2-x^2}</math> == | + | === <math>\sqrt{a^2-x^2}</math> === |
Making use of the identity <math>\displaystyle\sin^2\theta+\cos^2\theta=1</math>, simply let <math>x=a\sin\theta</math>. | Making use of the identity <math>\displaystyle\sin^2\theta+\cos^2\theta=1</math>, simply let <math>x=a\sin\theta</math>. | ||
+ | === <math>\sqrt{x^2-a^2}</math> === | ||
+ | Since <math>\displaystyle\sec^2(\theta)-1=\tan^2(\theta)</math>, let <math>x=a\sec\theta</math>. | ||
− | |||
− | |||
− | |||
{{stub}} | {{stub}} |
Revision as of 10:40, 13 July 2006
Trigonometric substitution is the technique of replacing variables in equations with or or other functions from trigonometry.
In calculus, it is used to evaluate integrals of expressions such as or
Contents
Examples
To evaluate an expression such as , we make use of the identity . Set and the radical will go away.
Making use of the identity , simply let .
Since , let .
This article is a stub. Help us out by expanding it.