Difference between revisions of "2011 AMC 10A Problems/Problem 2"
Golden ratio (talk | contribs) (→Solution) |
|||
Line 7: | Line 7: | ||
== Solution == | == Solution == | ||
− | You want to find the minimum number of small bottles: so you do <math>\frac{500}{35} \approx 14.3 </math> which you round to <math>15</math>. | + | You want to find the minimum number of small bottles: so you do <math>\frac{500}{35} \approx 14.3 </math> which you round (up for our purposes) to <math>15</math>. |
Revision as of 16:36, 2 February 2015
Problem 2
A small bottle of shampoo can hold 35 milliliters of shampoo, whereas a large bottle can hold 500 milliliters of shampoo. Jasmine wants to buy the minimum number of small bottles necessary to completely fill a large bottle. How many bottles must she buy?
Solution
You want to find the minimum number of small bottles: so you do which you round (up for our purposes) to .
The answer is .
See Also
2011 AMC 10A (Problems • Answer Key • Resources) | ||
Preceded by Problem 1 |
Followed by Problem 3 | |
1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 | ||
All AMC 10 Problems and Solutions |
The problems on this page are copyrighted by the Mathematical Association of America's American Mathematics Competitions.