Difference between revisions of "2007 AMC 12B Problems/Problem 3"
m (→Solution: making answer more obvious) |
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<math>\angle AOC=360-140-120=100=2\angle ABC</math> | <math>\angle AOC=360-140-120=100=2\angle ABC</math> | ||
| − | <math>\angle ABC=50 \Rightarrow \mathrm {D}</math> | + | <math>\angle ABC=50 \Rightarrow \boxed{\mathrm {D}}</math> |
==See Also== | ==See Also== | ||
Revision as of 12:44, 21 January 2015
Problem
The point 
is the center of the circle circumscribed about triangle 
, with 
and 
, as shown. What is the degree measure of 
?
Solution
See Also
| 2007 AMC 12B (Problems • Answer Key • Resources) | |
| Preceded by Problem 2 |
Followed by Problem 4 |
| 1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 | |
| All AMC 12 Problems and Solutions | |
The problems on this page are copyrighted by the Mathematical Association of America's American Mathematics Competitions. 
