Difference between revisions of "1993 UNCO Math Contest II Problems/Problem 5"
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== Solution == | == Solution == | ||
| + | To find the middle integer, we divide 1000 by 25 to get 40. We have found one number, so we know there are 24 more. We found the middle integer, so we know to find the largest and smallest we must add or subtract 24/2=12. Adding 12 gives us the largest is 52, and subtracting gives us the smallest is 28. | ||
== See also == | == See also == | ||
Revision as of 13:33, 30 December 2014
Problem
A collection of 
consecutive positive integers adds to 
What are the smallest and largest integers in this collection?
Solution
To find the middle integer, we divide 1000 by 25 to get 40. We have found one number, so we know there are 24 more. We found the middle integer, so we know to find the largest and smallest we must add or subtract 24/2=12. Adding 12 gives us the largest is 52, and subtracting gives us the smallest is 28.
See also
| 1993 UNCO Math Contest II (Problems • Answer Key • Resources) | ||
| Preceded by Problem 4 |
Followed by Problem 6 | |
| 1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 | ||
| All UNCO Math Contest Problems and Solutions | ||
