Difference between revisions of "2013 UNCO Math Contest II Problems/Problem 2"
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== Solution == | == Solution == | ||
We can factor 12 into 2*2*3. There are already two factors of two, so we only need to multiply it by 3 to get two factors of three, giving us 36. | We can factor 12 into 2*2*3. There are already two factors of two, so we only need to multiply it by 3 to get two factors of three, giving us 36. | ||
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| + | To find the perfect cube, we need all of the prime factors to be to the third power. Because 2 is squared, we need to multiply by a power of 2, giving us 2*12=24. Because we only have one power of three, we need two more, so we multiply 24*3*3, giving us 216, which is a perfect cube. | ||
== See Also == | == See Also == | ||
Revision as of 17:13, 23 December 2014
Problem
EXAMPLE: The number 
is equal to 
and also equal to 
, so is both a perfect square and a perfect cube.
(a) Find the smallest positive integer multiple of 
that is a perfect square.
(b) Find the smallest positive integer multiple of that is a perfect cube.
(c) Find the smallest positive integer multiple of that is both a perfect square and a perfect cube.
Solution
We can factor 12 into 2*2*3. There are already two factors of two, so we only need to multiply it by 3 to get two factors of three, giving us 36.
To find the perfect cube, we need all of the prime factors to be to the third power. Because 2 is squared, we need to multiply by a power of 2, giving us 2*12=24. Because we only have one power of three, we need two more, so we multiply 24*3*3, giving us 216, which is a perfect cube.
See Also
| 2013 UNCO Math Contest II (Problems • Answer Key • Resources) | ||
| Preceded by Problem 1 |
Followed by Problem 3 | |
| 1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 | ||
| All UNCO Math Contest Problems and Solutions | ||
