Difference between revisions of "2014 AMC 8 Problems/Problem 16"
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| − | + | The "Middle School Eight" basketball conference has <math>8</math> teams. Every season, each team plays every other conference team twice (home and away), and each team also plays <math>4</math> games against non-conference opponents. What is the total number of games in a season involving the "Middle School Eight" teams? | |
| − | + | <math>\textbf{(A) }60\qquad\textbf{(B) }88\qquad\textbf{(C) }96\qquad\textbf{(D) }144\qquad \textbf{(E) }160</math> | |
==See Also== | ==See Also== | ||
{{AMC8 box|year=2014|num-b=15|num-a=17}} | {{AMC8 box|year=2014|num-b=15|num-a=17}} | ||
{{MAA Notice}} | {{MAA Notice}} | ||
Revision as of 18:47, 26 November 2014
The "Middle School Eight" basketball conference has 
teams. Every season, each team plays every other conference team twice (home and away), and each team also plays 
games against non-conference opponents. What is the total number of games in a season involving the "Middle School Eight" teams?
See Also
| 2014 AMC 8 (Problems • Answer Key • Resources) | ||
| Preceded by Problem 15 |
Followed by Problem 17 | |
| 1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 | ||
| All AJHSME/AMC 8 Problems and Solutions | ||
The problems on this page are copyrighted by the Mathematical Association of America's American Mathematics Competitions. 
