Difference between revisions of "2005 CEMC Gauss (Grade 7) Problems/Problem 7"

(Created page with "== Problem == Karen has just been chosen the new “Math Idol”. A total of <math>1,480,000</math> votes were cast and Karen received <math>83\%</math> of them. How many people...")
 
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==See Also==
 
==See Also==
  
[[2005 CEMC Gauss (Grade 7)]]
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* [[2005 CEMC Gauss (Grade 7)]]
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* [[2005 CEMC Gauss (Grade 7) Problems]]
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* [[2005 CEMC Gauss (Grade 7) Problems/Problem 8]]

Revision as of 15:06, 22 October 2014

Problem

Karen has just been chosen the new “Math Idol”. A total of $1,480,000$ votes were cast and Karen received $83\%$ of them. How many people voted for her?

$\text{(A)}\ 830,000 \qquad \text{(B)}\ 1,228,400 \qquad \text{(C)}\ 1,100,000 \qquad \text{(D)}\ 251,600 \qquad \text{(E)}\ 1,783,132$

Solution

Since $83\%$ in decimal form is $0.83$, then the number of people who voted for Karen is equal to $0.83\times 1,480,000 = 1,228,400$. The answer is $B$.

See Also