Difference between revisions of "1958 AHSME Problems/Problem 11"

(Created page with "==Problem== The number of roots satisfying the equation <math> \sqrt{5 \minus{} x} \equal{} x\sqrt{5 \minus{} x}</math> is: <math> \textbf{(A)}\ \text{unlimited}\qquad \textbf...")
 
m (See also)
Line 27: Line 27:
 
==See also==
 
==See also==
  
{{AHSME box|year=1958|num-b=10|num-a=12}}
+
{{AHSME 50p box|year=1958|num-b=10|num-a=12}}
 
{{MAA Notice}}
 
{{MAA Notice}}

Revision as of 05:08, 3 October 2014

Problem

The number of roots satisfying the equation $\sqrt{5 \minus{} x} \equal{} x\sqrt{5 \minus{} x}$ (Error compiling LaTeX. Unknown error_msg) is:

$\textbf{(A)}\ \text{unlimited}\qquad  \textbf{(B)}\ 3\qquad  \textbf{(C)}\ 2\qquad  \textbf{(D)}\ 1\qquad  \textbf{(E)}\ 0$


Solution

Solve the equation for x.

\[\sqrt{5-x}=x\sqrt{5-x}\]

\[x\sqrt{5-x} - \sqrt{5-x} = 0\]

\[(x-1)\sqrt{5-x}=0\]

\[x=1,5\]

There are two solutions $\to \boxed{\textbf{(C)}}$


See also

1958 AHSC (ProblemsAnswer KeyResources)
Preceded by
Problem 10
Followed by
Problem 12
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 32 33 34 35 36 37 38 39 40 41 42 43 44 45 46 47 48 49 50
All AHSME Problems and Solutions

The problems on this page are copyrighted by the Mathematical Association of America's American Mathematics Competitions. AMC logo.png