Difference between revisions of "1970 AHSME Problems/Problem 30"

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== See also ==
 
== See also ==
{{AHSME 35p box|year=1970|num-b29|num-a=31}}   
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[[Category: Intermediate Geometry Problems]]
 
[[Category: Intermediate Geometry Problems]]
 
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{{MAA Notice}}

Revision as of 16:18, 2 October 2014

Problem

In the accompanying figure, segments $AB$ and $CD$ are parallel, the measure of angle $D$ is twice that of angle $B$, and the measures of segments $AD$ and $CD$ are $a$ and $b$ respectively. Then the measure of $AB$ is equal to

$\text{(A) } \tfrac{1}{2}a+2b\quad \text{(B) } \tfrac{3}{2}b+\tfrac{3}{4}a\quad \text{(C) } 2a-b\quad \text{(D) } 4b-\tfrac{1}{2}a\quad \text{(E) } a+b$

Solution

$\fbox{E}$

See also

1970 AHSC (ProblemsAnswer KeyResources)
Preceded by
Problem 29
Followed by
Problem 31
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All AHSME Problems and Solutions

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