Difference between revisions of "1968 AHSME Problems/Problem 22"
(Created page with "== Problem == A segment of length <math>1</math> is divided into four segments. Then there exists a quadrilateral with the four segments as sides if and only if each segment is:...") |
m (→Solution) |
||
| Line 11: | Line 11: | ||
== Solution == | == Solution == | ||
| − | <math>\fbox{}</math> | + | <math>\fbox{E}</math> |
== See also == | == See also == | ||
Revision as of 02:32, 29 September 2014
Problem
A segment of length 
is divided into four segments. Then there exists a quadrilateral with the four segments as sides if and only if each segment is:
Solution
See also
| 1968 AHSME (Problems • Answer Key • Resources) | ||
| Preceded by Problem 21 |
Followed by Problem 23 | |
| 1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 • 26 • 27 • 28 • 29 • 30 | ||
| All AHSME Problems and Solutions | ||
The problems on this page are copyrighted by the Mathematical Association of America's American Mathematics Competitions. 
