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Difference between revisions of "1968 AHSME Problems/Problem 18"

(Created page with "== Problem == Side <math>AB</math> of triangle <math>ABC</math> has length 8 inches. Line <math>DEF</math> is drawn parallel to <math>AB</math> so that <math>D</math> is on segm...")
 
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== Solution ==
 
== Solution ==
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<math>\fbox{}</math>
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<math>\fbox{D}</math>
  
 
== See also ==
 
== See also ==

Revision as of 02:31, 29 September 2014

Problem

Side $AB$ of triangle $ABC$ has length 8 inches. Line $DEF$ is drawn parallel to $AB$ so that $D$ is on segment $AC$, and $E$ is on segment $BC$. Line $AE$ extended bisects angle $FEC$. If $DE$ has length $5$ inches, then the length of $CE$, in inches, is:

$\text{(A) } \frac{51}{4}\quad \text{(B) } 13\quad \text{(C) } \frac{53}{4}\quad \text{(D) } \frac{40}{3}\quad \text{(E) } \frac{27}{2}$

Solution

$\fbox{D}$

See also

1968 AHSME (Problems • Answer Key • Resources)
Preceded by
Problem 17 		Followed by
Problem 19
1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 • 26 • 27 • 28 • 29 • 30
All AHSME Problems and Solutions

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