Difference between revisions of "1991 AHSME Problems/Problem 19"
(Created page with "== Problem == <asy> draw((0,0)--(0,3)--(4,0)--cycle,dot); draw((4,0)--(7,0)--(7,10)--cycle,dot); draw((0,3)--(7,10),dot); MP("C",(0,0),SW);MP("A",(0,3),NW);MP("B",(4,0),S);MP("E"...") |
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== Solution == | == Solution == | ||
| − | <math>\fbox{}</math> | + | <math>\fbox{B}</math> |
== See also == | == See also == | ||
Revision as of 14:55, 28 September 2014
Problem
![[asy] draw((0,0)--(0,3)--(4,0)--cycle,dot); draw((4,0)--(7,0)--(7,10)--cycle,dot); draw((0,3)--(7,10),dot); MP("C",(0,0),SW);MP("A",(0,3),NW);MP("B",(4,0),S);MP("E",(7,0),SE);MP("D",(7,10),NE); [/asy]](http://latex.artofproblemsolving.com/2/e/f/2ef7aca957cbf3c8f375b7437b66b0db4f5e96f3.png)
Triangle 
has a right angle at 
and 
. Triangle 
has a right angle at 
and 
. Points 
and 
are on opposite sides of 
. The line through parallel to 
meets 
extended at 
. If
![\[\frac{DE}{DB}=\frac{m}{n},\]](http://latex.artofproblemsolving.com/5/0/2/50279c9036f28da01bb745285a4aa85a576a5254.png)
where 
and 
are relatively prime positive integers, then 
Solution
See also
| 1991 AHSME (Problems • Answer Key • Resources) | ||
| Preceded by Problem 18 |
Followed by Problem 20 | |
| 1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 • 26 • 27 • 28 • 29 • 30 | ||
| All AHSME Problems and Solutions | ||
The problems on this page are copyrighted by the Mathematical Association of America's American Mathematics Competitions. 
