Difference between revisions of "User talk:Bobthesmartypants/Sandbox"
(→origami) |
(→combo) |
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draw((-0.5,0.7)..(-0.3,0.3)..(-0.05,0.05),Arrow());</asy> | draw((-0.5,0.7)..(-0.3,0.3)..(-0.05,0.05),Arrow());</asy> | ||
− | == | + | ==combos== |
+ | |||
+ | <asy>label("$C$",(0,0)); | ||
+ | label("$C$",(1,-1)); | ||
+ | label("$O$",(1,0)); | ||
+ | label("$O$",(2,-1)); | ||
+ | label("$O$",(0,1)); | ||
+ | label("$M$",(2,0)); | ||
+ | label("$M$",(1,1)); | ||
+ | label("$M$",(0,2)); | ||
+ | label("$M$",(3,-1)); | ||
+ | label("$B$",(3,0)); | ||
+ | label("$B$",(2,1)); | ||
+ | label("$B$",(1,2)); | ||
+ | label("$B$",(0,3)); | ||
+ | label("$B$",(4,-1)); | ||
+ | label("$O$",(4,0)); | ||
+ | label("$O$",(3,1)); | ||
+ | label("$O$",(2,2)); | ||
+ | label("$O$",(1,3)); | ||
+ | label("$O$",(0,4)); | ||
+ | label("$O$",(5,-1)); | ||
+ | label("$*$",(0,-1)); | ||
+ | </asy> |
Revision as of 18:35, 12 May 2014
Contents
Bobthesmartypants's Sandbox
Solution 1
First, continue to hit at . Also continue to hit at .
We have that . Because , we have .
Similarly, because , we have .
Therefore, .
We also have that because is a parallelogram, and .
Therefore, . This means that , so .
Therefore, .
Solution 2
Note that is rational and is not divisible by nor because .
This means the decimal representation of is a repeating decimal.
Let us set as the block that repeats in the repeating decimal: .
( written without the overline used to signify one number so won't confuse with notation for repeating decimal)
The fractional representation of this repeating decimal would be .
Taking the reciprocal of both sides you get .
Multiplying both sides by gives .
Since we divide on both sides of the equation to get .
Because is not divisible by (therefore ) since and is prime, it follows that .
Picture 1
Picture 2
physics problem
Solution
inscribed triangle
moar images
yay
solution reflection
origami
combos