Difference between revisions of "1991 AHSME Problems/Problem 7"
(Created page with "\If <math>x=\frac{a}{b}</math>, <math>a\neq b</math> and <math>b\neq 0</math>, then <math>\frac{a+b}{a-b}=</math> (A) <math>\frac{x}{x+1}</math> (B) <math>\frac{x+1}{x-1}</math>...") |
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(A) <math>\frac{x}{x+1}</math> (B) <math>\frac{x+1}{x-1}</math> (C) <math>1</math> (D) <math>x-\frac{1}{x}</math> (E) <math>x+\frac{1}{x}</math> | (A) <math>\frac{x}{x+1}</math> (B) <math>\frac{x+1}{x-1}</math> (C) <math>1</math> (D) <math>x-\frac{1}{x}</math> (E) <math>x+\frac{1}{x}</math> | ||
+ | {{MAA Notice}} |
Revision as of 12:52, 5 July 2013
\If , and , then
(A) (B) (C) (D) (E) The problems on this page are copyrighted by the Mathematical Association of America's American Mathematics Competitions.