Difference between revisions of "2002 AMC 8 Problems/Problem 13"

Line 10: Line 10:
 
==See Also==
 
==See Also==
 
{{AMC8 box|year=2002|num-b=12|num-a=14}}
 
{{AMC8 box|year=2002|num-b=12|num-a=14}}
 +
{{MAA Notice}}

Revision as of 23:45, 4 July 2013

Problem

For his birthday, Bert gets a box that holds 125 jellybeans when filled to capacity. A few weeks later, Carrie gets a larger box full of jellybeans. Her box is twice as high, twice as wide and twice as long as Bert's. Approximately, how many jellybeans did Carrie get?

$\text{(A)}\ 250\qquad\text{(B)}\ 500\qquad\text{(C)}\ 625\qquad\text{(D)}\ 750\qquad\text{(E)}\ 1000$

Solution

Assume Bert's box is $1 \times 1 \times 1$ which is $1$ cubic meter. Then his box holds $125$ jellybeans per cubic meter. Carrie has a box that is $2 \times 2 \times 2$ which is $8$ cubic meters. Her box holds eight times as many jellybeans as Carrie's which is $(8)(125)=\boxed{\text{(E)}\ 1000}$.

See Also

2002 AMC 8 (ProblemsAnswer KeyResources)
Preceded by
Problem 12
Followed by
Problem 14
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25
All AJHSME/AMC 8 Problems and Solutions

The problems on this page are copyrighted by the Mathematical Association of America's American Mathematics Competitions. AMC logo.png